How do you solve #4x + 2= 12x + 3#?

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Answer 1 · 2018-03-25T09:55:09

#x=-1/8#

We have:

#4x+2=12x+3#

#8x+3=2#

#8x=-1#

#x=-1/8#

Answer 2 · 2018-03-25T10:00:58

#x=-1/8#

Solving an equation means finding all the possible values of the variable to satisfy the provided conditions.

The given equation is

#4x+2=12x+3#

Now let's begin with eliminating #3# from the RHS by subtracting #3# from both sides.

#4x+2-3=12x+3-3#

#4x-1=12x#

Next, let's bring the variable terms together by subtracting #4x# from both sides

#4x-1-4x=12x-4x#

#-1=8x#

By dividing by #8# on both sides of the equation, we get

#(-1)/8 = (8x)/8#

#-1/8=x#