How do you solve #4x^2-4x+1>=0#?
1 Answer
Dec 22, 2016
This inequality holds for all
#4x^2-4x+1 = (2x-1)^2 >= 0#
Explanation:
You might recognise this perfect square trinomial, since:
#441 = 21^2#
So:
#4x^2-4x+1 = (2x-1)^2#
