How do you solve #4x +8 <= 6x -20#?

1 Answer
Nov 8, 2017

Answer:

#x >=14#

Explanation:

Pretend that your #<=# here is just a plain old #=#. Balance it like you always would :)

#4x+8<=6x-20# Subtract #6x# from both sides

#-2x+8<=-20# Subtract #8# from both sides

#-2x<=-28# Divide both sides by #-2# and do not forget to flip the sign because you're dividing by a negative number!

#x >= 14#