How do you solve #5sqrt(x+1)=21#?

Question

1810 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-12T01:09:21

#x=416/25#

Solve:

#5sqrt(x+1)=21#

Square both sides.

#25(x+1)=441#

Divide both sides by #25#

#x+1=441/25#

Subtract #1# from both sides.

#x=441/25-1#

Multiply #1# by #25/25# to get an equivalent fraction with #25# as the denominator.

#x=441/25-1xx25/25#

#x=441/25-25/25#

Simplify.

#x=416/25#

Answer 2 · 2018-05-12T01:14:08

Answer = 16.64

#5 √(x+1) =21#

Divide:

#(5√x+1)/5 = 21/5 or 4.2#

Square (the opposite of square root):

#(√(x+1))^2= 4.2^2 or 17.64#

Subtract:

#x+1-1=17.64-1#

#x=16.64#