How do you solve #-6(4x+1)=5-11x#?

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Answer 1 · 2017-02-11T12:34:20

See the entire solution process below:

First, expand the terms in parenthesis on the left side of the equation:

#(-6 xx 4x) + (-6 xx 1) = 5 - 11x#

#-24x - 6 = 5 - 11x#

Next, add #color(red)(24x)# and subtract #color(blue)(5)# from each side of the equation to isolate the #x# term.

#-24x - 6 + color(red)(24x) - color(blue)(5) = 5 - 11x + color(red)(24x) - color(blue)(5)#

#-24x + color(red)(24x) - 6 - color(blue)(5) = 5 - color(blue)(5) - 11x + color(red)(24x)#

#0 - 11 = 0 + 13x#

#-11 = 13x#

Now, divide each side of the equation by #color(red)(13)# to solve for #x# while keeping the equation balanced:

#-11/color(red)(13) = (13x)/color(red)(13)#

#-11/13 = (color(red)(cancel(color(black)(13)))x)/cancel(color(red)(13))#

#-11/13 = x#

#x = -11/13#