# How do you solve 6(y+2)-4=-10?

Apr 19, 2016

$y = - 3$

#### Explanation:

These are the steps to solve this:
1. Expand everything out
$6 \left(y + 2\right) - 4 = - 10$
$6 y + 12 - 4 = - 10$
2. Move everything that doesn't have a $y$ in it to the right side, and everything with a $y$ to the left side.
$6 y = - 10 + 4 - 12$
$6 y = - 18$
$y = - 3$

There are other methods of solving the question though; here's another.
$6 \left(y + 2\right) = - 10 + 4$
$6 \left(y + 2\right) = - 6$
$y + 2 = - 1$
$y = - 3$
But as you can see, it doesn't matter which method you use, as long as you show full working out when solving it, and there is no mathematical errors in your proof.