# How do you solve 63-x=2x+3?

Apr 15, 2016

We can solve this by remembering to always to the same thing to both sides of the equation leading to $x = 20$

#### Explanation:

We can solve this by remembering to always do the same thing to both sides of the equation. Lets start by adding $x$ to both sides, since it is easy to see that this will eliminate the $x$ from the left-hand side:

$63 - x + x = 2 x + 3 + x$

which gives

$63 = 3 x + 3$

now we can subtract $3$ from both sides giving

$63 - 3 = 3 x + 3 - 3$

$60 = 3 x$

Let's divide both sides by 3 this time:

$\frac{60}{3} = \frac{3 x}{3}$

$20 = x$

We are also allowed to write the equation in the opposite order giving

$x = 20$

We can check our answer by substituting it into the original:

$63 - x = 2 x + 3$

$63 - 20 = 2 \cdot 20 + 3$

$43 = 43$ Correct!