Question

How do you solve `6x^2+5x=1`?

Answer 1

Re-arranging we get:

`6x^2 + 5x - 1 = 0`

We can write this as:

`6x^2 + 6x - x - 1 = 0`

i.e. `6x(x + 1) - (x + 1) = 0`

=> `(6x - 1)(x + 1) = 0`

so, `x = 1/6 or x = -1`

:)>

Answer 2

`x=-1" or " x=1/6`

Explanation:

`"subtract 1 from both sides and equate to zero"`

`6x^2+5x-1=1-1`

`rArr6x^2+5x-1=0`

`"using the a-c method of factorising"`

`"require the factors of the product " -6" which sum to +5"`

`"the factors are " +6, -1`

`rArr6x^2+6x-x-1=0larr" split 5x"`

`rArr6x(x+1)-1(x+1)=0larr" factor pairs"`

`(x+1)(6x-1)=0larr" factor out (x+1)"`

`(x+1)=0rArrx=-1`

`(6x-1)=0rArrx=1/6`

`rArrx=-1" or " x=1/6" are the solutions"`