How do you solve #7-3x=x-4(2+x)#?

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Answer 1 · 2016-07-02T00:47:52

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To solve #7-3x=x-4(2+x)#

Begin by distributing the #4#

#7-3x=x-8-4x#

Combine like terms

#7-3x=-3x-8#

Combine the variables and constants on opposite sides of the equal sign

#7 + 8 cancel(-3x) cancel(+3)=-3x +3x cancel(-8) cancel(+8)#

#15=0x#

No Solution