How do you solve #7a-3=3+6a#?

1 Answer
EZ as pi
Oct 5, 2016

#a =6#

Explanation:

To solve an equation you need to have all the variable on one side and the numbers on the other side.

#7a-3 color(red)(-6a)= 3+6acolor(red)(-6a)" "larr# subtract 6a from both sides

#7a-6a -3 color(blue)(+3)=3color(blue)(+3)" "larr# add 3 to both sides

#a = 6" "larr# this is the solution..

The solution is the value of a which makes the equation true.

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