How do you solve $7x ^ { 2} - 10x = - 3$ ?

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Answer 1 · 2017-03-03T17:20:40

$x=1$

$7x^2-10x=-3$

$7x^2-10x+3=0$

$(7x-3)(x-1)=0$

$7x-3=0$ or $x-1=0$

$7x=3$ or $x=1$

$x=3/7$ or $x=1$

substitute x=3/7

$7(3/7)^2-10(3/7)=-3$

$7(9/7)-30/7=-3$

$63/7-30/7=-3$

$33/7=-3$

$4 4/7=-3$

$x=3/7$ = Extraneous solution

substitute $x=1$

$7(1)^2-10(1)=-3$

$7-10=-3$

$-3=-3$

$:.x=1$

How do you solve 7x ^ { 2} - 10x = - 37x ^ { 2} - 10x = - 3?