How do you solve $- 8 - 7 x = - 5 x - 10$ $-8-7x=-5x-10$ ?

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Answer 1 · 2016-12-10T14:03:49

$x = 1$ $x = 1$

First, isolate the $x$ $x$ terms and the constants on different sides of the equation while keeping the equation balanced:

$- 8 - 7 x + 7 x + 10 = - 5 x - 10 + 7 x + 10$ $-8 - 7x + 7x + 10 = -5x - 10 + 7x + 10$

$- 8 - 0 + 10 = - 5 x + 7 x - 0$ $-8 - 0 + 10 = -5x + 7x - 0$

$- 8 + 10 = - 5 x + 7 x$ $-8 + 10 = -5x + 7x$

We can now combine terms and solve for $x$ $x$ while keeping the equation balanced:

$2 = (- 5 + 7) x$ $2 = (-5 + 7)x$

$2 = 2 x$ $2 = 2x$

$\frac{2}{2} = \frac{2 x}{x}$ $2/2 = (2x)/x$

$1 = (cancel(2)x)/cancel(2)$

$x = 1$

How do you solve -8-7x=-5x-10−8−7x=−5x−10-8-7x=-5x-10?