How do you solve #8( x + 11) > 32#?

2 Answers
Mar 16, 2017

Answer:

#x> -7#

Explanation:

The first step is to distribute the bracket.

#rArr8x+88>32#

subtract 88 from both sides of the inequality.

#8xcancel(+88)cancel(-88)>32-88#

#rArr8x> -56#

divide both sides by 8

#(cancel(8) x)/cancel(8)=(-56)/8#

#rArrx> -7" is the solution"#

Mar 16, 2017

Answer:

#x > -7#

Explanation:

#8(x+11)>32 #

#8x+88>32#

#8x>32-88#

#8x > -56#

#(cancel(8)x)/cancel(8) > -(56)/8#

#x > -7#