# How do you solve 8z=4(2z+1)?

Feb 5, 2017

See the entire solution process below:

#### Explanation:

First, expand the terms within parenthesis on the right hand side of the equation:

$8 z = \left(4 \times 2 z\right) + \left(4 \times 1\right)$

$8 z = 8 z + 4$

Now, subtract $8 z$ from each side of the equation:

$- 8 z + 8 z = - 8 z + 8 z + 4$

$0 = 0 + 4$

$0 = 4$

However, we know $0 \ne 4$, therefore there is no solution to this equation, or $x$ equals the null set, or $x = \left\{\emptyset\right\}$