How do you solve a triangle given B=150 degrees, a=10, c=20?
Draw a diagram to represent the situation.
We have to start by finding side B with cosine's law.
b = 29.093
Now, we can use Sine's law to solve for angles A and C
A = 9.896˚ = 10˚
B = 180 - 150 - 10
B = 20˚
So, b = 29.093, A = 10˚ and B = 20˚.
- Solve each triangle. Round angles to the closest degree and sides to the nearest thousandth. Beware of the ambiguous case of the Sine's
a) a = 29 cm, b = 34 cm and c = 15 cm
b) A = 27˚, b = 44 cm et c = 25 cm
c) a = 57 cm, b = 48 cm, B = 86˚