How do you solve and find the value of $sin(sin^-1(1/2))$ ?

Question

17248 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-16T06:56:42

$sin(sin^(-1)(1/2))=1/2$

$sin^(-1)(1/2)$ means an angle $theta$ so that $sintheta=1/2$

As we have $sin(pi/6)=1/2$ , $sin^(-1)(1/2)=pi/6$

and $sin(sin^(-1)(1/2))=sin(pi/6)=1/2$

How do you solve and find the value of sin(sin^-1(1/2))sin(sin^-1(1/2))?