# How do you solve and graph #-2a+3>=6a-1>3a-10#?

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Add

Add 1 to both sides

Divide both sides by 8

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Subtract

Add 1 to both sides

Divide both sides by 3

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In the same order as in the question.

Lets 'rotate' it horizontally

You use a 'hollow' circle at the end for 'greater than' or 'less than'.

You use a 'filled in' circle at the end for 'less than or equal to' or 'greater than or equal to'.

The feasible region for

To construct this I used:

AND

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Describe your changes (optional) 200

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Answer is

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means

i.e.

or

Also

or

or

Hence answer is

Describe your changes (optional) 200