# How do you solve and graph k+3/4>1/3?

Nov 3, 2017

See a solution process below:

#### Explanation:

Subtract $\textcolor{red}{\frac{3}{4}}$ from each side of the inequality to solve for $k$ while keeping the inequality balanced:

$k + \frac{3}{4} - \textcolor{red}{\frac{3}{4}} > \frac{1}{3} - \textcolor{red}{\frac{3}{4}}$

$k + 0 > \left(\frac{4}{4} \times \frac{1}{3}\right) - \left(\frac{3}{3} \times \textcolor{red}{\frac{3}{4}}\right)$

$k > \frac{4}{12} - \frac{9}{12}$

$k > - \frac{5}{12}$

To graph this we will draw a vertical line at $- \frac{5}{12}$ on the horizontal axis.

The line will be a dashed line because the inequality operator does not contain an "or equal to" clause.

We will shade to the right side of the line because the inequality operator has a "greater than" clause:

graph{x>=-5/12 [-2, 2, -1, 1]}