# Four consecutive integers are such that the sum of the #2#nd and #4#th integers is #132#. What are the four integers?

##### 2 Answers

Sep 13, 2016

#### Explanation:

Suppose the integers are:

#n-2, n-1, n, n+1#

Then we are given:

#132 = (n-1) + (n+1) = 2n#

Dividing both ends by

#n = 66#

So the four integers are:

#64, 65, 66, 67#

Sep 13, 2016

The four consecutive integers are 64,65, 66 and 67.

#### Explanation:

Consecutive integers are found by adding 1. For example, 2, 3 and 4 are consecutive integers.

For this problem:

Let the first =x

Let the second integer =x+1

Let the third integer =x+2

Let the fourth integer =x+3

The sum of the 2nd and 4th is

Combine like terms

Subtract 4 from both sides.

Divide both sides by 2.

The first integer is 64.

The 2nd is 65.

The 3rd is 66.

The 4th is 67.