How do you solve #b/sin45=21/sin100#?

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Answer 1 · 2018-01-27T11:36:51

#b=15.1(1dp)#

this is an exercise in rearranging and using a calculator

#b/(sin45)=21/sin100#

multiply both sides by #sin45#

#b/cancel((sin45)) xxcancel(sin45)=21/sin100xxsin45#

#=>b=(21sin45)/sin100#

using a calculator we find

#b=15.0783159=15.1(1dp)#