How do you solve by factoring #2y^3+7y^2-30y=0#?

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Answer 1 · 2018-05-02T14:10:33

#y=0 or -6 or 5/2#

#2y^3+7y^2-30y=0#

Factor #y# out,

#y(2y^2+7y-30)=0#

Factor further,

#y(y+6)(2y-5)=0#

Solve,

#y=0 or -6 or 5/2#