How do you solve dilution problems in chemistry? For example: if 211 mL of water is added to 5.00 mL of 3.24 M NaCl solution, what is the concentration of the dilute solution? ____ M.

1 Answer
anor277
May 10, 2017

"Concentration"-=0.0750*mol*L^-1........

Explanation:

The defining formula is "Concentration"="Moles of solute"/"Volume of solution"; or C=n/V, and thus for your problem we work out....

C_2=(C_1xxV_1)/(V_1+V_2)=(5.00xx10^-3*Lxx3.24*mol*L^-1)/((211+5)xx10^-3L)=0.0750*mol*L^-1

The numerator addresses the number of moles of solute, and the volume are added in the denominator. Note that the answer is consistent dimensionally............1*mL=10^-3*L

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