# How do you solve for a in (10ac-x)/ 11 = -3?

Feb 17, 2016

This is just standard algebra, but the answer will be expressed in terms of $c$ and $x$. See below for the full calculation. $a = \frac{x - 33}{10 c}$

#### Explanation:

Starting equation. Our goal is to get $a$ 'naked'. ;)

$\frac{10 a c - x}{11} = - 3$

Multiply both sides by 11:

$10 a c - x = - 33$

Add $x$ to both sides:

$10 a c = x - 33$

Divide both sides by $10 c$:

$a = \frac{x - 33}{10 c}$