# How do you solve for b in 3ab–z = y(4ab +2z)?

Feb 14, 2016

You must first distribute the parentheses.

#### Explanation:

$3 a b - z = 4 a b y + 2 y z$

Put the terms containing b on one side of the equation.

$3 a b - 4 a b y = 2 y z + z$

Factor out the b.

$b \left(3 a - 4 a y\right) = 2 y z + z$

$b = \frac{2 y z + z}{3 a - 4 a y}$ or $b = \frac{z \left(2 y + 1\right)}{a \left(3 - 4 y\right)}$

Practice exercises:

1. Solve for x.

a) $\frac{2 x + 3 y}{4 x - y} = \frac{x + 3 y}{2 x - 5 y}$

b). $\frac{2 x + 3 y + 2 z}{x} + \frac{4 x - 5 y + 3 z}{y} = \frac{x - 3 y - 2 z}{z}$

Good luck!