How do you solve for d in #ax+b=cx+d #?

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Answer 1 · 2016-09-25T03:20:21

#d=(a-c)x+b#

Given: #ax+b=cx+d#

Subtract #cx# from both sides #-> ax+b -cx =cx+d-cx#

#ax+b-cx = d#

Group terms in #x#:

#ax-cx+b =d#
#(a-c)x + b=d#

#:. d=(a-c)x+b#

NB: With little practice you should be able to skip some of these steps