How do you solve for f in C= 5/9 (f-32)?

Mar 18, 2016

See solution below.

Explanation:

$C = \frac{5}{9} \left(f - 32\right)$

$\frac{C}{f - 32} = \frac{5}{9}$

Use the property $\frac{a}{b} = \frac{m}{n} \to a \times n = b \times m$

$9 C = 5 f - 160$

$9 C + 160 = 5 f$

$\frac{9 C + 160}{5} = f$

$\frac{9}{5} C + 32 = f$

Practice exercises:

$1.$ The formula for conversion between Celsius, $c$ and farenheight $f$, is $C = \frac{5}{9} \left(f - 32\right)$. Find how many farenheight would be 5 degrees Celsius.

$2.$ Solve for x. Hint: try putting on the same denominator.

$\frac{1}{x} + \frac{1}{x y} = \frac{1}{x + y}$

Good luck!