How do you solve for f in #C= 5/9 (f-32)#?

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Answer 1 · 2016-03-18T14:44:52

See solution below.

#C = 5/9(f - 32)#

#C/(f - 32) = 5/9#

Use the property #a/b = m/n -> a xx n = b xx m#

#9C = 5f - 160#

#9C + 160 = 5f#

#(9C + 160)/5= f#

#9/5C + 32 = f#

Practice exercises:

#1.# The formula for conversion between Celsius, #c# and farenheight #f#, is #C = 5/9(f - 32)#. Find how many farenheight would be 5 degrees Celsius.

#2.# Solve for x. Hint: try putting on the same denominator.

#1/x + 1/(xy) = 1/(x + y)#

Good luck!