How do you solve for k in #h + p = 3 (k-8)#?

Question

5514 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-14T00:03:53

You must first distribute.

#h + p = 3(k - 8)#

#h + p = 3k - 24#

#h + p + 24 = 3k#

#(h + p + 24)/3 = k#

Practice exercises:

a) #zx = yz - yx#

b) #2/x + 3/y = -5/z#

Good luck!