# How do you solve for k in h + p = 3 (k-8)?

Feb 14, 2016

You must first distribute.

#### Explanation:

$h + p = 3 \left(k - 8\right)$

$h + p = 3 k - 24$

$h + p + 24 = 3 k$

$\frac{h + p + 24}{3} = k$

Practice exercises:

1. Solve for x in the following equations:

a) $z x = y z - y x$

b) $\frac{2}{x} + \frac{3}{y} = - \frac{5}{z}$

Good luck!