How do you solve for m in #K=1/2 m^2#?

2 Answers
Aug 29, 2016

Answer:

#m= (2*K)^0.5#

Explanation:

Let me compute m step by step.

#m^2 = 2*K#

Now square root both sides:

#m = (2*K)^0.5#

Aug 29, 2016

Answer:

#m = +-sqrtK#

Explanation:

Isolate m, step by step. This is also called making #m# the subject of the formula.

It feels more comfortable to have #m# on the left hand side. We may just turn the equation around to achieve this.

#K = 1/2 m^2#

#1/2 m^2 = K color(white)(............................................) xx2#

#cancel2 xx 1/cancel2 m^2 = K xx2#

#m^2 = Kcolor(white)(............................................) "find" sqrt#

#m = +-sqrtK#