# How do you solve for x in #5ax-c=4c+ax #?

##### 1 Answer

Mar 17, 2016

#### Explanation:

#5ax-c=4c+ax#

#5ax# #color(red)(-ax)-c=4c+ax# #color(red)(-ax)#

#4ax-c=4c#

#4ax-c# #color(blue)(+c)=4c# #color(blue)(+c)#

#4ax=5c#

#(4ax)/color(darkorange)(4a)=(5c)/color(darkorange)(4a)#

#color(green)(|bar(ul(color(white)(a/a)x=(5c)/(4a)color(white)(a/a)|)))#