How do you solve for x in #5ax-c=4c+ax #?

1 Answer
Mar 17, 2016

Answer:

#x=(5c)/(4a#

Explanation:

#1#. Group all like terms together. Start by subtracting #ax# from both sides of the equation.

#5ax-c=4c+ax#

#5ax# #color(red)(-ax)-c=4c+ax# #color(red)(-ax)#

#4ax-c=4c#

#2#. Continue grouping all like terms together by adding #c# to both sides.

#4ax-c# #color(blue)(+c)=4c# #color(blue)(+c)#

#4ax=5c#

#3#. Isolate for #x# by dividing both sides by #4a#.

#(4ax)/color(darkorange)(4a)=(5c)/color(darkorange)(4a)#

#color(green)(|bar(ul(color(white)(a/a)x=(5c)/(4a)color(white)(a/a)|)))#