# How do you solve for x in 5ax-c=4c+ax ?

Mar 17, 2016

x=(5c)/(4a

#### Explanation:

$1$. Group all like terms together. Start by subtracting $a x$ from both sides of the equation.

$5 a x - c = 4 c + a x$

$5 a x$ $\textcolor{red}{- a x} - c = 4 c + a x$ $\textcolor{red}{- a x}$

$4 a x - c = 4 c$

$2$. Continue grouping all like terms together by adding $c$ to both sides.

$4 a x - c$ $\textcolor{b l u e}{+ c} = 4 c$ $\textcolor{b l u e}{+ c}$

$4 a x = 5 c$

$3$. Isolate for $x$ by dividing both sides by $4 a$.

$\frac{4 a x}{\textcolor{\mathrm{da} r k \mathmr{and} a n \ge}{4 a}} = \frac{5 c}{\textcolor{\mathrm{da} r k \mathmr{and} a n \ge}{4 a}}$

$\textcolor{g r e e n}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} x = \frac{5 c}{4 a} \textcolor{w h i t e}{\frac{a}{a}} |}}}$