Question

How do you solve for x in `C=b-bx`?

Answer 1

`x = 1 - C/b`

Explanation:

Let's start by rewriting as

`bx - b = -C`

Now factor

`b(x- 1) = -C`

`x - 1 = -C/b`

`x = 1 - C/b`

Hopefully this helps!

Answer 2

`x = 1 - C/b`

Explanation:

You can separate the constants from the variable with algebraic operations. In this case we will still end up with an expression in C and b, as they are not given values.

`C = b - bx = b(1 - x)` (distributive property)
`C/b = 1 - x` (divide both sides by b)
`C/b - 1 = - x` (subtract 1 from both sides)
`x = 1 - C/b` (multiply both sides by -1 and rearrange for neatness)

NOW, given any C and b, x can be calculated directly.