# How do you solve for x in m^2x-3m^2=12m^2?

Feb 26, 2016

$x = 15$
${m}^{2} x - 3 {m}^{2} = 12 {m}^{2}$
$\rightarrow \cancel{{m}^{2}} \left(x - 3\right) = 12 \cancel{{m}^{2}}$
$\rightarrow x = 15$