How do you solve for x in x/(3-j) = (j/2)?

Mar 13, 2016

$x = \frac{3 j - {j}^{2}}{2}$

Explanation:

$\frac{x}{3 - j} = \frac{j}{2}$

Isolating $x$ on the L.H.S:

$x = \left(\frac{j}{2}\right) \cdot \left(3 - j\right)$

$x = \frac{3 j - {j}^{2}}{2}$