Question

How do you solve for x in `y=(e^x-e^-x)/6`?

Answer 1

`x = sinh^-1(3y)`

Explanation:

`3y = (e^x - e^-x)/2`

It has been found that `sinhx = (e^x- e^-x)/2`, where `y = sinhx` is the hyperbolic sine function.

Thus,

`3y = sinhx`

`sinh^-1(3y) = x`

I'm not entirely sure that this is the answer you want. If you want something else, write a note and I'll change the answer accordingly.

Hopefully this helps!