How do you solve for y in #3x - 2y = 10#?

1 Answer
Mar 13, 2018

Answer:

See a solution process below:

Explanation:

First, subtract #color(red)(3x)# from each side of the equation to isolate the #y# term while keeping the equation balanced:

#3x - 2y = 10#

#-color(red)(3x) + 3x - 2y = -color(red)(3x) + 10#

#0 - 2y = -3x + 10#

#-2y = -3x + 10#

Now, divide each side of the equation by #color(red)(-2)# to solve for #y# while keeping the equation balanced:

#(-2y)/color(red)(-2) = (-3x + 10)/color(red)(-2)#

#(color(red)(cancel(color(black)(-2)))y)/cancel(color(red)(-2)) = (-3x)/color(red)(-2) + 10/color(red)(-2)#

#y = (-3)/color(red)(-2)x + (-5)#

#y = 3/2x - 5#