How do you solve for y in $3x - 2y = 10$ ?

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Answer 1 · 2018-03-13T12:33:37

See a solution process below:

First, subtract $color(red)(3x)$ from each side of the equation to isolate the $y$ term while keeping the equation balanced:

$3x - 2y = 10$

$-color(red)(3x) + 3x - 2y = -color(red)(3x) + 10$

$0 - 2y = -3x + 10$

$-2y = -3x + 10$

Now, divide each side of the equation by $color(red)(-2)$ to solve for $y$ while keeping the equation balanced:

$(-2y)/color(red)(-2) = (-3x + 10)/color(red)(-2)$

$(color(red)(cancel(color(black)(-2)))y)/cancel(color(red)(-2)) = (-3x)/color(red)(-2) + 10/color(red)(-2)$

$y = (-3)/color(red)(-2)x + (-5)$

$y = 3/2x - 5$

How do you solve for y in 3x - 2y = 103x - 2y = 10?