# How do you solve for z in y^2 + 3yz - 8z - 4x = 0?

$3 y z - 8 z = 4 x - {y}^{2}$
$z \left(3 y - 8\right) = 4 x - {y}^{2}$
$z = \frac{4 x - {y}^{2}}{3 y - 8}$