How do you solve for z in #y^2 - 4x = 8z - 3yz#?

2 Answers
May 10, 2017

Answer:

Not possible

Explanation:

For each variable you want to solve for, a separate equation is needed. For example, if you want to solve for #x# in #x=5*2#, you only need one equation. If you wanted #x# and #y#, you would need a system of two equations. If you wanted three variables, you need three equations, so on and so forth.

May 10, 2017

Answer:

Use distributive property on the right-hand side and isolate #z#.

Explanation:

First we can use the distributive property to take out the #z# on the right-hand side:
#y^2-4x=z(8-3y)#

To isolate the #z#, we can divide over the #8-3y#:
#z=(y^2-4x)/(8-3y)#, where #y!=8/3# which gives us the expression for z