How do you solve #\frac { x - 2} { 5} = \frac { 2x - 1} { 11}#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer carly · Stefan V. May 15, 2018 #x = 17# Explanation: Multiply the left-hand numerator #(x -2)# by #11#. Multiply the right-hand numerator #(2x-1)# by #5#. So #11x-22=10x -5# #11x-22-10x=10x -5-10x# #x - 22 = -5# So #x - 22+22 = -5+22# # x= 17# You can substitute #17# in to original equation to check: # (17-2)/5 =(17xx2-1)/11 # # 3=3# Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 263 views around the world You can reuse this answer Creative Commons License