How do you solve inequality #x^2+x+1>0#?

1 Answer
Aug 16, 2015

Answer:

Solve the inequality: #f(x) = x^2 + x + 1 > 0#

Explanation:

First, find the 2 x-intercepts (real roots) by solving
#f(x) = x^2 + x + 1 = 0#.
D = d^2 = b^2 - 4ac = 1 - 4 = -3.
There is no x-intercepts. Since a > 0, the parabola opens upward and is completely above the x-axis.
The inequality f(x) > 0 is always true, regardless of x.
graph{x^2 + x + 1 [-10, 10, -5, 5]}