# How do you solve m+4(2m-3)=-3?

Jan 7, 2017

See full solution process below:

#### Explanation:

First, we will expand the terms in parenthesis:

$m + \textcolor{red}{4} \left(2 m - 3\right) = - 3$

$m + \left(\textcolor{red}{4} \times 2 m\right) - \left(\textcolor{red}{4} \times 3\right) = - 3$

$m + 8 m - 12 = - 3$

We can now combine like terms:

$1 m + 8 m - 12 = - 3$

$\left(1 + 8\right) m - 12 = - 3$

$9 m - 12 = - 3$

Next we can isolate the $m$ term and keep the equation balanced by adding $\textcolor{red}{12}$ to each side of the equation:

$9 m - 12 + \textcolor{red}{12} = - 3 + \textcolor{red}{12}$

$9 m - 0 = 9$

$9 m = 9$

Now we can solve for $m$ while keeping the equation balanced by dividing each side of the equation by $\textcolor{red}{9}$:

$\frac{9 m}{\textcolor{red}{9}} = \frac{9}{\textcolor{red}{9}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{9}}} m}{\cancel{\textcolor{red}{9}}} = 1$

$m = 1$