Question

How do you solve `m+4(2m-3)=-3`?

Answer 1

See full solution process below:

Explanation:

First, we will expand the terms in parenthesis:

`m + color(red)(4)(2m - 3) = -3`

`m + (color(red)(4) xx 2m) - (color(red)(4) xx 3) = -3`

`m + 8m - 12 = -3`

We can now combine like terms:

`1m + 8m - 12 = -3`

`(1 + 8)m - 12 = -3`

`9m - 12 = -3`

Next we can isolate the `m` term and keep the equation balanced by adding `color(red)(12)` to each side of the equation:

`9m - 12 + color(red)(12) = -3 + color(red)(12)`

`9m - 0 = 9`

`9m = 9`

Now we can solve for `m` while keeping the equation balanced by dividing each side of the equation by `color(red)(9)`:

`(9m)/color(red)(9) = 9/color(red)(9)`

`(color(red)(cancel(color(black)(9)))m)/cancel(color(red)(9)) = 1`

`m = 1`