How do you solve #n^2-120=7n#?
Whenever we're dealing with quadratics, we want to set them equal to zero, to find the zeroes.
We can start by subtracting
Now, we need to think of two numbers that sum up to
After some trial and error, we arrive at
Now, we have the following:
To find the zeroes, we just take the inverse signs to get:
Hope this helps!
-8 and 15.
Solve this equation by the new Transforming Method (Socratic, Google Search), case a = 1.
Find 2 real roost, that have opposite signs (ac < 0), knowing their sum (- b = 7) and their product (c = -120).
They are: - 8 and 15.
Note . This method avoids the lengthy factoring by grouping and solving the 2 binomials.