How do you solve root3(y-7)=4?

Nov 13, 2017

$y = 71$

Explanation:

raising both terms to the cube

$\left(y - 7\right) = {4}^{3}$

${4}^{3} = 64$

$\left(y\right) = 64 + 7$

$\left(y\right) = 71$

Nov 13, 2017

$y = 71$

Explanation:

$\sqrt[3]{y - 7} = 4$

or, ${\left(\sqrt[3]{y - 7}\right)}^{3} = {4}^{3}$

or, $y - 7 = 64$

or, $y = 64 + 7 = 71$

So the value of $y$ is $71$.