# How do you solve s+1/6<=2/3?

Feb 9, 2017

See the entire solution process below:

#### Explanation:

First, subtract $\textcolor{red}{\frac{1}{6}}$ from each side of the inequality to solve for $s$ while keeping the inequality balanced:

$s + \frac{1}{6} - \textcolor{red}{\frac{1}{6}} \le \frac{2}{3} - \textcolor{red}{\frac{1}{6}}$

$s + 0 \le \frac{2}{3} - \frac{1}{6}$

Multiply $\frac{2}{3}$ by the appropriate form of $1$ to put both fractions over a common denominator so they can be added together:

$s \le \left(\frac{2}{2} \times \frac{2}{3}\right) - \frac{1}{6}$

$s \le \frac{4}{6} - \frac{1}{6}$

$s \le \frac{3}{6}$

$s \le \frac{1}{2}$