# How do you solve #-s^2+4s-6>0#?

##### 1 Answer

Apr 10, 2017

#### Answer:

Never

#### Explanation:

Using the discriminant to determine how many zeros the function has.

where

Since the discriminant is negative, there are no real roots for this function (the quadratic will never cross the x-axis). Therefore the function will NEVER be greater than

Here is a graphical look,

graph{-x^2+4x-6 [-10, 10, -5, 5]}