# How do you solve sintheta=0.8 for 90<theta<180?

${126.87}^{0}$
Sin $\theta$=.8 gives the value of the reference angle $\theta$ as ${53.13}^{o}$. The required angle between ${90}^{0}$ and ${180}^{o}$ would be 180-53.13 = ${126.87}^{0}$