How do you solve sintheta=0.8 for 90<theta<180? Trigonometry Inverse Trigonometric Functions Basic Inverse Trigonometric Functions 1 Answer bp Oct 1, 2017 126.87^0 Explanation: Sin theta=.8 gives the value of the reference angle theta as 53.13^o. The required angle between 90^0 and 180^o would be 180-53.13 = 126.87^0 Answer link Related questions What are the Basic Inverse Trigonometric Functions? How do you use inverse trig functions to find angles? How do you use inverse trigonometric functions to find the solutions of the equation that are in... How do you use inverse trig functions to solve equations? How do you evalute sin^-1 (-sqrt(3)/2)? How do you evalute tan^-1 (-sqrt(3))? How do you find the inverse of f(x) = \frac{1}{x-5} algebraically? How do you find the inverse of f(x) = 5 sin^{-1}( frac{2}{x-3} )? What is tan(arctan 10)? How do you find the arcsin(sin((7pi)/6))? See all questions in Basic Inverse Trigonometric Functions Impact of this question 7208 views around the world You can reuse this answer Creative Commons License