How do you solve #sqrt(2x+1)+sqrt(2x+6)=5#?

1 Answer
Feb 9, 2017

Answer:

x= 3/2

Explanation:

  1. Try move one square to the other side: #sqrt(2x+1)=5-sqrt(2x+6)#
  2. Take a square and you will get: #2x+1=25+2x+6-10*sqrt(2x+6)#
  3. And now the 2xs are cancelled on both sides, rearrange and you will get: #10*sqrt(2x+6)=30#
  4. Now the equation is simple, take a square on both sides and you will get the answer.