How do you solve #sqrt(3x+1)=5#?

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Answer 1 · 2015-07-18T00:03:42

#x=8#

#sqrt(3x+1)=5#

Square both sides.

#3x+1=5^2#

#3x+1=25#

Subtract #1# from both sides.

#3x=25-1# =

#3x=24#

Divide both sides by #3#.

#x=24/3# =

#x=8#