Question

How do you solve `sqrt(5x^2 - 40)= 0`?

Answer 1

`x = 2sqrt(2)` and `x = -2sqrt(2)`

Explanation:

Square both sides:

`5x^2 - 40 = 0`

`5x^2 = 40`

`x^2 = 8`

`x = +- sqrt(8)`

`x = +-2sqrt(2)`

Both these solutions are valid as they satisfy the original equation.

Hopefully this helps!

Answer 2

`x = +- sqrt(8)`

Explanation:

1. First, square both sides of the equation, so `5x^2-40=0`
2. Add `40` to both sides: `5x^2=40`
3. Divide by `5` on both sides: `x^2=8`
4. Square root on both sides: `x= +- sqrt(8)`