How do you solve #sqrt(5x^2 - 40)= 0#?

2 Answers
Mar 12, 2018

Answer:

#x = 2sqrt(2)# and #x = -2sqrt(2)#

Explanation:

Square both sides:

#5x^2 - 40 = 0#

#5x^2 = 40#

#x^2 = 8#

#x = +- sqrt(8)#

#x = +-2sqrt(2)#

Both these solutions are valid as they satisfy the original equation.

Hopefully this helps!

Answer:

#x = +- sqrt(8)#

Explanation:

  1. First, square both sides of the equation, so #5x^2-40=0#
  2. Add #40# to both sides: #5x^2=40#
  3. Divide by #5# on both sides: #x^2=8#
  4. Square root on both sides: #x= +- sqrt(8)#