How do you solve #\sqrt { - 5x - 9} = 11#?

1 Answer
Dec 19, 2016

Answer:

#x=-26#

Explanation:

Given -

#sqrt(-5x-9)=11#

To eliminate the root, square both sides

#(sqrt(-5x-9))^2=11^2#

#-5x-9=121#

Add #9 #to both sides

#-5x-9+9=121+9#
#-5xcancel(-9) cancel(+9)=130#
Divide both sides by #-5#
#(-5x)/(-5)=130/(-5)#
#(cancel(-5)x)/cancel(-5)=130/(-5)#
#x=-26#