# How do you solve sqrt(x^2 +3) =x+1?

Oct 2, 2016

${\left(\sqrt{{x}^{2} + 3}\right)}^{2} = {\left(x + 1\right)}^{2}$

${x}^{2} + 3 = {x}^{2} + 2 x + 1$

$2 = 2 x$

$x = 1$

Checking in the original equation, you will find $x = 1$ satisfies the equation.

Hopefully this helps!