# How do you solve sqrt4=sqrt(x+2) and check your solution?

Apr 20, 2017

#### Answer:

$x = 2$

#### Explanation:

Raise both sides to the power of $^ 2$, doing so reduces the square roots on both sides of the equation to $1$ and makes this problem simplier without changing the question.

${\left(\sqrt{4}\right)}^{2} = {\left(\sqrt{x + 2}\right)}^{2}$

$4 = x + 2$

$x = 2$

Checking the solution by substituiting $x = 2$ into the original problem,

sqrt4=sqrt(2+2

$\sqrt{4} = \sqrt{4}$

Therefore $x = 2$ is the solution